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  1. 0.44 x 2 Faraday / 1 mol = 0.88 Faradays

    0.88 Faradays ( 96500 Coulombs/ Faraday) = 85000 C

How many coulombs (C) of electrical charge must pass through an electrolytic cell?

How many coulombs (C) of electrical charge must pass through an electrolytic cell to reduce 0.44 mol Ca2+ ion to calcium metal?

a- 190,000 C
b- 85,000 C
c- 21,000 C
d- 42,500 C
e- 0.88 C
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