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  1. The maximum useful work will be given by the negative of the change in the Gibbs free energy of the system. Since we are assuming that the system is at the STP of 1 atm and 25°C, the change in the Gibbs free energy of the system will simply be the standard Gibbs free energy of formation of water, which is -237.1 kJ/mole. Since water has a molecular weight of 18.01528, we produce
    1.67 * 1000 / 18.01528 = 92.7 moles of water,
    so the maximum useful work obtainable is
    92.7 * 237.1 = 22,000 kJ.

What is the maximum useful work which can be obtained from a hydrogen-oxygen fuel cell that produces 1.67 kg o

What is the maximum useful work which can be obtained from a hydrogen-oxygen fuel cell that produces 1.67 kg of water at 25°C?

(Assume 1 atm pressure for the gases.)
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