When a uranium nucleus at rest breaks apart in the process known as fission in a nuclear reactor, the resulting fragments have a total kinetic energy of about 205 MeV. How much mass was lost in the process?
(may be broke/outdated!)
When a uranium nucleus at rest breaks apart in the process known as fission in a nuclear reactor, the resulting fragments have a total kinetic energy of about 205 MeV. How much mass was lost in the process?
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2 Responses
kinetic energy of the resulting fragments is 205 Mev which is previously stored in the nucleus as a potential energy because of the force between proton-proton because of their electric charge and force between proton-proton , proton-neutron , neutron-neutron because of their quarks structure before fission occurs…and when it occurs then the energy produces due to lose of mass….
So, as an equation of Einstein..E=m.c^2 where, m=lose of mass
so, m=[(205 * 10^6)(1.6 * 10^-19)] / 9 *10^16
(Here, we have to convert the unit system of energy from Mev to joule in order to use this equation)
= 36.444 * 10^-29 kg
= 3.64 * 10^-28 kg
assuming from your question that all of the loss of mass was converted to KE of the fission fragements,
one atomic mass unit (amu) equals 931.46 Mev
so …… 205MeV/931.46MeV/amu = 0.220084598 amu
1 amu = 1.66E-27Kg
so 1.66E-27Kg/amu * 0.220084598 amu = 3.65459E-28Kg
usually, the KE of the fission fragments accounts for 85% of the total energy released in fission of U235